32=25x^2

Solution for 32=25x^2 equation:

32=25x^2

We move all terms to the left:

32-(25x^2)=0

a = -25; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·(-25)·32
Δ = 3200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3200}=\sqrt{1600*2}=\sqrt{1600}*\sqrt{2}=40\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{2}}{2*-25}=\frac{0-40\sqrt{2}}{-50}
=-\frac{40\sqrt{2}}{-50}
=-\frac{4\sqrt{2}}{-5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{2}}{2*-25}=\frac{0+40\sqrt{2}}{-50}
=\frac{40\sqrt{2}}{-50}
=\frac{4\sqrt{2}}{-5}
$